Recently, the AJAX structures appear to be utilized all over the place. Indeed, the vast majority of the PHP custom web application advancement ventures are presently being created with AJAX structures. Furthermore, on the off chance that you take a gander at any Jquery Ajax Post model, you'll notice that the code looks simpler, more limited, and more comprehensible.
For instance, undertakings, for example, making a catch for various program XMLHttpRequest, opening any URL, checking if the solicitation is prepared or not have the short and more discernible linguistic structure in Jquery Ajax.
Today, in our PHP instructional exercise, we'll be demonstrated the execution cycle for submitting AJAX forms in PHP with Jquery Ajax Post Example or you can say Jquery submit structure Ajax.
In this Ajax model demo, we'll use the serialize() technique for making URL encoded text string by serializing structure esteems. These serialized qualities can be utilized in the URL inquiry string at whatever point you're making an AJAX demand for submitting AJAX forms in PHP.
Prior to beginning, share it with your companions with simply a solitary snap!
Let's get started
Here we will discuss step by step method for submitting AJAX forms in PHP. So let’s get started without any delay:
#1 Make a document with Index.php to show the feed in the program.
If the feed is not visible in the program then make a document with “Index.php” to show the feed in the program.
Presently, characterize a header for the page.
Code:
<html>
<head>
<title>Space-O | Ajax submit form</title>
</head>
<style type="text/css">
table { border-collapse: collapse; }
table, th, td { border: 1px solid black; }
</style>
<body>
<h1>jQuery post form data using .ajax() method</h1>
#2 make a structure for acquiring subtleties from the end-client.
For submitting AJAX forms in PHP, don’t forget to make a structure for acquiring subtleties from the end-user.
Code
<form id='userForm'>
<div>
<input type='text' name='name' placeholder='Name'/>
</div>
<div>
<input type='text' name='email'placeholder='Email' />
</div>
<div>
<input type='text' name='number' placeholder='Mobile Number' />
</div>
<div>
<input type='submit' value='Submit' />
</div>
</form>
#3 Make a Div to show data that is entered by end-client and achievement message.
The third and most important step for submitting AJAX forms in PHP, make a Div to show data that is entered by the end-user and also show a success message.
Below is the code to make div and success message:
Code
<div id='response'></div>
Integrate Javascript to use Jquery.
code
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js "></script>
#4 the entire usage, as well as a standard of code, is defined below:
This the final step where we are providing you with a standard code below for submitting AJAX forms in Php:
Code
<script>
$(document).ready(function(){
$('#userForm').submit(function(){
// show that something is loading
$('#response').html("<b>Loading response...</b>");
// Call ajax for pass data to other place
$.ajax({
type: 'POST',
url: 'get_information.php',
data: $(this).serialize() // getting filed value in serialize form
})
.done(function(data){ // if getting done then call.
// show the response
$('#response').html(data);
})
.fail(function() { // if fail then getting message
// just in case posting your form failed
alert( "Posting failed." );
});
// to prevent refreshing the whole page page
return false;
});
});
</script>
Full code of Jquery AJAX Post Example:
Below is the full code of Jquery AJAX post example that will help you to know how to submit AJAX forms in PHP.
Code
<html>
<head>
<title>Space-O | Ajax submit form</title>
</head>
<body>
<h1>jQuery post form data using .ajax() method</h1>
<!-- our form -->
<form id='userForm'>
<div><input type='text' name='name' placeholder='Name' /></div>
<div><input type='text' name='email' placeholder='Email' /></div>
<div><input type='text' name='number' placeholder='Mobile Number' /></div>
<div><input type='submit' value='Submit' /></div>
</form>
<style type="text/css">
table {
border-collapse: collapse;
}
table, th, td {
border: 1px solid black;
}
</style>
<!-- where the response will be displayed -->
<div id='response'></div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js "></script>
<script>
$(document).ready(function(){
$('#userForm').submit(function(){
// show that something is loading
$('#response').html("<b>Loading response...</b>");
// Call ajax for pass data to other place
$.ajax({
type: 'POST',
url: 'get_information.php',
data: $(this).serialize() // getting filed value in serialize form
})
.done(function(data){ // if getting done then call.
// show the response
$('#response').html(data);
})
.fail(function() { // if fail then getting message
// just in case posting your form failed
alert( "Posting failed." );
});
// to prevent refreshing the whole page page
return false;
});
});
</script>
</body>
</html>
Bottom Line
This is all done now you are set to use the set of code accordingly to submit ajax forms in PHP and as per your preference. You can also edit some words and code and can do the experiment if you are learning PHP or if you are a well-trained PHP developer or coder. I hope this blog helped you in solving your queries if you have still any queries regarding submitting AJAX forms in PHP you can contact us by submitting your details and query on the contact us page.
